Kayla Pine #59
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kyra-patton
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Jul 28, 2022
| @@ -2,18 +2,46 @@ | |||
| def grouped_anagrams(strings): | |||
| """ This method will return an array of arrays. | |||
| Each subarray will have strings which are anagrams of each other | |||
| Time Complexity: ? | |||
| Space Complexity: ? | |||
| Time Complexity: O(n^2)? The fucntion only loops through the length of strings for | |||
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⏱ Sorting is an O(n) operation, however if we assume all strings are valid english words, we can say this is an O(1) operation because n will never be very large.
Therefore you just have the for loop through the elements of strings which would make this O(n)
| Space Complexity: ? | ||
| Time Complexity: O(n^2)? The fucntion only loops through the length of strings for | ||
| the number of letters in each string? | ||
| Space Complexity: O(n)? Theres only 2 varaibles being stored...sortedWord and anagramsHash? |
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🪐 Yes! anagramsHash can have at most n elements where n is the length of strings. Overall the combined length of the values will also be n elements.
| Time Complexity: ? | ||
| Space Complexity: ? | ||
| Time Complexity: O(n) | ||
| Space Complexity: O(n^2)? |
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Space complexity would be O(n). finalList will be of length k which can never be greater than the length of nums. freqHash will have at most n key value pairs as well, where the values are all integers.
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