Automated update

Author: JakubDotPy

output/common_directory_path.py

@@ -0,0 +1,35 @@
+"""Kata - Common directory path
+
+completed at: 2024-09-05 12:19:57
+by: Jakub Červinka
+
+Returns the commom directory path for specified array of full filenames.
+```
+ @param {array} pathes
+ @return {string}
+```
+Examples:
+ ```
+   ['/web/images/image1.png', '/web/images/image2.png']  => '/web/images/'
+   ['/web/assets/style.css', '/web/scripts/app.js',  'home/setting.conf'] => ''
+   ['/web/assets/style.css', '/.bin/mocha',  '/read.me'] => '/'
+   ['/web/favicon.ico', '/web-scripts/dump', '/webalizer/logs'] => '/'
+```
+(c)RSS
+"""
+
+import os
+
+def get_common_directory_path(paths): 
+    try:
+        common_path = os.path.commonpath(paths)        
+        common_path_with_sep = common_path + os.sep
+    
+        # Check if all paths start with the common path + separator
+        if all(p.startswith(common_path_with_sep) for p in paths):
+            return common_path_with_sep
+
+        return common_path
+        
+    except ValueError:
+        return ''

output/k_permutations_of_n.py

@@ -0,0 +1,23 @@
+"""Kata - k-permutations of n
+
+completed at: 2024-09-05 16:19:23
+by: Jakub Červinka
+
+Implement a function `k_permutations_of_n` that accepts a list of elements `lst` and an integer `k`, and returns all permutations of elements from the list `lst`. Permutations should be a list containing all unique lists of `k` elements from `lst`, in any order.
+
+For example, if `lst == [1,2,3]` and `k == 2` the result should be:
+
+```python
+[[1, 2], [1, 3], [2, 1], [2, 3], [3, 1], [3, 2]]
+```
+
+* if `k > len(lst)` the function should return an empty list, i.e.`[]`
+* if `k == 0`, the function should return `[[]]`, because there is exactly `1` way to arrange `0` elements (remember that `0! == 1`).
+
+You can assume that the input list `lst` contains unique elements.
+"""
+
+from itertools import permutations
+
+def k_permutations_of_n(lst : list, k : int) -> list:
+	return list(map(list, permutations(lst, k)))

output/the_coupon_code.py

@@ -0,0 +1,48 @@
+"""Kata - The Coupon Code
+
+completed at: 2024-09-05 15:32:13
+by: Jakub Červinka
+
+# Story
+
+Your online store likes to give out coupons for special occasions. Some customers try to cheat the system by entering invalid codes or using expired coupons.
+
+# Task
+
+Your mission:  
+Write a function called `checkCoupon` which verifies that a coupon code is valid and not expired.
+
+A coupon is no more valid on the day **AFTER** the expiration date.  All dates will be passed as strings in this format: `"MONTH DATE, YEAR"`.
+
+## Examples:
+
+```javascript
+checkCoupon("123", "123", "July 9, 2015", "July 9, 2015")  ===  true
+checkCoupon("123", "123", "July 9, 2015", "July 2, 2015")  ===  false
+```
+```typescript
+checkCoupon("123", "123", "July 9, 2015", "July 9, 2015")  ===  true
+checkCoupon("123", "123", "July 9, 2015", "July 2, 2015")  ===  false
+```
+```csharp
+CheckCoupon("123", "123", "July 9, 2015", "July 9, 2015")  ==  true
+CheckCoupon("123", "123", "July 9, 2015", "July 2, 2015")  ==  false
+```
+```python
+checkCoupon("123", "123", "July 9, 2015", "July 9, 2015")  == True
+checkCoupon("123", "123", "July 9, 2015", "July 2, 2015")  == False
+```
+"""
+
+from datetime import datetime
+
+def check_coupon(entered_code, correct_code, current_date, expiration_date):
+    # check code match
+    code_match = entered_code is correct_code
+    
+    # check date validity
+    current_date = datetime.strptime(current_date, '%B %d, %Y')
+    expiration_date = datetime.strptime(expiration_date, '%B %d, %Y')
+    is_fresh = current_date <= expiration_date
+    
+    return code_match and is_fresh