2180. Count Integers With Even Digit Sum (C).c

int countEven(int num) {
    int count = 0;
        int digitSum = 0;
        
        for (int i = 1; i <= num; ++i) {
            int temp = i;
            int sum = 0;
            
            // Calculate the sum of digits of `i`
            while (temp > 0) {
                sum += temp % 10;
                temp /= 10;
            }
            
            // Increment count if the sum of digits is even
            if (sum % 2 == 0) {
                ++count;
            }
        }
        
        return count;
    }