Session 9 Report

[far2000]

Team Name: [FILL HERE]

Student Name of member 1: Amirhossein Farahani
Student No. of member 1: 97106154

Student Name of member 2: Saba Molaei
Student No. of member 2: 99100947

• Read Session Contents.

Section 9.3

• I can't understand the question, so I upload screenshot from code:

• Printing all linux interrupts

  • I found the Linux interrupt file according to the available manual and then read it line by line. Then, by running this executable file in C language, I displayed all the interrupts available in the operating system in the output.

  • This is the output after executing code

• Requirements (I can't understand it exactly, but I answer it in general)

1.   access to /proc/interrupts
   

2.   gcc
   

3.   access to execute code
   

Section 9.4

I used this code to make some interrupts by using softirq, but I got an error after trying to makefile. I can't debug it but I guess in Debian 12 (my version of Debian) I can't access interrupts headers. description: the first function defines a custom SoftIRQ handler (`my_softirq_handler`) to process the SoftIRQ when raised. The module initializes the SoftIRQ during loading (`my_softirq_init`) using `open_softirq`, raises it with `raise_softirq`, and cleans up the resources during module unloading (`my_softirq_exit`). also I should mention that, we can't call this interrupt with user level program. this interrupt only manage by kernel.

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• Adding a new interrupt - in this section i use another method to simulate interrupt with assembly.

- [ ] `I Just use svc for calling an interrupt`
- [ ] `FILL HERE with screenshot of execution`

- [ ] `Requirements: just like the previous section`