14链表中倒数第k个结点.py

# -*- coding:utf-8 -*-
__author__ = 'ShawDa'
# class ListNode:
#     def __init__(self, x):
#         self.val = x
#         self.next = None


class Solution:
    def FindKthToTail(self, head, k):
        # write code here
        slow, fast = head, head
        for i in range(k):
            if fast == None:
                return None
            fast = fast.next
        while fast:
            fast = fast.next
            slow = slow.next
        return slow