717.1-比特与-2-比特字符.py

#
# @lc app=leetcode.cn id=717 lang=python3
#
# [717] 1 比特与 2 比特字符
#
from typing import List


# @lc code=start
class Solution:
    def isOneBitCharacter(self, bits: List[int]) -> bool:
        i, n = 0, len(bits)
        while i < n - 1:
            i += bits[i] + 1
        return i == n - 1


# @lc code=end