The problem asks for the maximum length of a concatenated string formed by combining strings from the given list, such that the concatenated string contains only unique characters.
The solution uses backtracking to explore all possible combinations of strings. The backtrack
function is defined with two parameters: index
, which keeps track of the current position in the arr
list, and current_string
, which represents the concatenated string formed so far.
The function first checks if current_string
contains unique characters by comparing the length of current_string
with the length of the set of characters in current_string
. If they don't match, the function returns 0, as it means there's a duplicate character.
If current_string
is unique, the function iterates through the remaining strings in the arr
ay starting from the current index
. For each string, it recursively calls backtrack
, adding the current string from arr
to current_string
. The maximum length is updated accordingly.
This approach systematically explores all combinations, ensuring that each combination is checked for uniqueness before considering its length.
- Time Complexity:
, where is the number of strings in the array and is the average length of the strings. This complexity arises because, in the worst case, the algorithm explores all possible combinations of strings, and for each combination, it takes time to check for unique characters and calculate the length. - Space Complexity:
, which is the maximum depth of the recursion stack multiplied by the length of the current_string
. In the worst case, the recursion goeslevels deep, and the length of the current_string
could be up toat each level of recursion.
class Solution:
def maxLength(self, arr: List[str]) -> int:
def backtrack(index, current_string):
unique_length = len(set(current_string))
if unique_length != len(current_string):
return 0
max_length = len(current_string)
for i in range(index, len(arr)):
max_length = max(max_length, backtrack(i + 1, current_string + arr[i]))
return max_length
return backtrack(0, "")