-
Notifications
You must be signed in to change notification settings - Fork 0
/
Copy pathpat_basic_1035.cpp
181 lines (175 loc) · 3.7 KB
/
pat_basic_1035.cpp
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
120
121
122
123
124
125
126
127
128
129
130
131
132
133
134
135
136
137
138
139
140
141
142
143
144
145
146
147
148
149
150
151
152
153
154
155
156
157
158
159
160
161
162
163
164
165
166
167
168
169
170
171
172
173
174
175
176
177
178
179
180
181
#include <iostream>
#include <algorithm>
using namespace std;
int cmp(int a, int b) {
return a < b;
}
int main() {
int n;
cin >> n;
int *a = new int [n];
int *b = new int [n];
for (int i = 0; i < n; i++) {
cin >> a[i];
}
for (int i = 0; i < n; i++) {
cin >> b[i];
}
int i, j;
for (i = 0; i < n - 1 && b[i] <= b[i + 1]; i++);
for (j = i + 1; a[j] == b[j] && j < n; j++);
if (j == n) {
cout << "Insertion Sort" << endl;
sort(a, a + i + 2, cmp);
} else {
cout << "Merge Sort" << endl;
int k = 1;
int flag = 1;
while(flag) {
flag = 0;
for (i = 0; i < n; i++) {
if (a[i] != b[i])
flag = 1;
}
k = k * 2;
for (i = 0; i < n / k; i++)
sort(a + i * k, a + (i + 1) * k, cmp);
sort(a + n / k * k, a + n, cmp);
}
}
for (j = 0; j < n - 1; j++) {
cout << a[j] << " ";
}
cout << a[n - 1];
return 0;
}
//===============================================================================================================
//上面是网上找到的答案,下面是我自己的。没有用sort函数自己实现归并排序的下一步所以代码略长
#include <stdio.h>
#include <iostream>
using namespace std;
//排序完成之后输出
void print(int * in, int n){
bool isfirst = true;
for (int i = 0; i < n; i++)
{
if (isfirst){
cout << in[i];
isfirst = false;
}
else{
cout << ' ' << in[i];
}
}
}
//判断是否为插入排序,不是则是归并排序
int isinsert(int * in1, int * in2, int n){
int loc = -1;//如果不是插入排序则返回-1,否则返回插入排序的位置信息
int i;
for (i = 0; i < n - 1; i++)
{
if (in2[i] > in2[i + 1]){
loc = i;
break;
}
}
//如果输入和排序后的序列完全一致则为插入排序,返回1
if (i == n - 1){
loc = 1;
}
else{
for (int j = loc + 1; j < n; j++)
{
if (in1[j] != in2[j]){
loc = -1;
break;
}
}
}
return loc;
}
void insertion(int *in2, int loc){
int temp = in2[loc + 1];
int i = loc;
while (in2[i] > temp){
in2[i + 1] = in2[i];
i--;
}
in2[i + 1] = temp;
}
void merge(int * in2, int n){
int L, i;//代表归并段长度
int *mgr = (int*)malloc(n*sizeof(int));
for (L = 2; L < n; L *= 2)
{
for (i = L; i < n; i += 2 * L)
{
if (in2[i - 1] > in2[i]){
break;
}
}
if (i < n){
break;
}
}
//继续下一步的归并,此时的归并段长度为L
//cout << L<<endl;
int j = 0, k = L, m = 0;//m代表新数组中的位置
int j0 = j + L, k0 = k + L;
while (k < n){
for (; j < j0 && k < k0 && k < n;)
{
mgr[m] = in2[j] < in2[k] ? in2[j++] : in2[k++];
m += 1;
}
if (j == j0){
for (; k < k0&&k<n; k++)//这里的K<N的情况和容易遗忘,否则测试点5 和6 通不过
{
mgr[m] = in2[k];
m += 1;
}
}
else if (k == k0||k==n){
for (; j < j0; j++)
{
mgr[m] = in2[j];
m += 1;
}
}
j = k;
k = k + L;
j0 = j + L, k0 = k + L;
}
for (; j < j0; j++)
{
mgr[m] = in2[j];
m += 1;
}
print(mgr, n);
free(mgr);
}
int main(){
int n, loc;//loc记录插入排序的中间步骤的进行位置
cin >> n;
int *in1 = (int *)malloc(n*sizeof(int));
int *in2 = (int *)malloc(n*sizeof(int));
for (int i = 0; i < n; i++)
{
cin >> in1[i];
}
for (int i = 0; i < n; i++)
{
cin >> in2[i];
}
loc = isinsert(in1, in2, n);
if (loc != -1){
cout << "Insertion Sort" << endl;
insertion(in2, loc);
print(in2, n);
}
else{
cout << "Merge Sort" << endl;
merge(in2, n);
}
return 0;
}