-
Notifications
You must be signed in to change notification settings - Fork 0
Example: Longest Increasing Subsequence
Roberto Fronteddu edited this page Apr 14, 2024
·
2 revisions
Given a sequence, find the longest ordered subsequence. Example: 3, 4, -1, 0, 6, 2, 3 => -1, 0, 2, 3
package leetcode_exercises.dp;
import java.util.ArrayList;
import java.util.Collections;
import java.util.List;
public class LongestIncreasingSubsequence
{
public static int lis (int[] nums) {
int[] dp = new int[nums.length];
int endIndex = 0;
int maxLen = 0;
for (int i = 0; i < nums.length; i++) {
dp[i] = 1;
}
for (int i = 1; i < nums.length; i++) {
for (int j = 0; j < i; j++) {
if (nums[j] < nums[i] && dp[j] + 1 > dp[i]) {
dp[i] = dp[j] + 1;
if (dp[i] > maxLen) {
maxLen = dp[i];
endIndex = i;
}
}
}
}
// reconstruct LIS
List<Integer> lis = new ArrayList<> ();
lis.add (nums[endIndex]);
int len = maxLen - 1;
for (int i = endIndex - 1; i >= 0; i--) {
if (dp[i] == len && nums[i] < lis.get (lis.size () - 1)) {
lis.add (nums[i]);
len--;
}
}
Collections.reverse(lis);
lis.forEach (x -> System.out.print (x + " "));
return dp[nums.length - 1];
}
}